Is it possible to use the rule 231/1.6 with a condition for the checked component?
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Is it possible to use the rule 231/1.6 with a condition for the checked component?
e.g. I want to check all the rooms “which are closed with only window openings” if they have a door,
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@Anees-Alomar said in Is it possible to use the rule 231/1.6 with a condition for the checked component?:
which are closed with only window openings
I dont’ understand this clear enough. Could you describe more detail what is the problem that the rule would solve / check?
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Hi Matti, thanks for your reply, I use this rule to check if each room has a door, but we have many rooms as open space and don’t have doors. So my question was: is it possible to check “only rooms that are closed with at least 4 walls”?
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